2[2x-(3x-2)]=9(x-2)

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Solution for 2[2x-(3x-2)]=9(x-2) equation:


Simplifying
2[2x + -1(3x + -2)] = 9(x + -2)

Reorder the terms:
2[2x + -1(-2 + 3x)] = 9(x + -2)
2[2x + (-2 * -1 + 3x * -1)] = 9(x + -2)
2[2x + (2 + -3x)] = 9(x + -2)

Reorder the terms:
2[2 + 2x + -3x] = 9(x + -2)

Combine like terms: 2x + -3x = -1x
2[2 + -1x] = 9(x + -2)
[2 * 2 + -1x * 2] = 9(x + -2)
[4 + -2x] = 9(x + -2)

Reorder the terms:
4 + -2x = 9(-2 + x)
4 + -2x = (-2 * 9 + x * 9)
4 + -2x = (-18 + 9x)

Solving
4 + -2x = -18 + 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.
4 + -2x + -9x = -18 + 9x + -9x

Combine like terms: -2x + -9x = -11x
4 + -11x = -18 + 9x + -9x

Combine like terms: 9x + -9x = 0
4 + -11x = -18 + 0
4 + -11x = -18

Add '-4' to each side of the equation.
4 + -4 + -11x = -18 + -4

Combine like terms: 4 + -4 = 0
0 + -11x = -18 + -4
-11x = -18 + -4

Combine like terms: -18 + -4 = -22
-11x = -22

Divide each side by '-11'.
x = 2

Simplifying
x = 2

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